How do you simplify #sqrt(6) *sqrt(32)#?

Question

2798 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-29T14:33:38

Remember that #sqrt(a)*sqrt(b)=sqrt(a*b)#
So:
#sqrt(6)*sqrt(32)=sqrt(6*32)=sqrt(192)=sqrt(4*4*4*3)=2*2*2*sqrt(3)=8sqrt(3)#