How do you simplify #sqrt(80w^3)/9#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. May 26, 2015 #sqrt(80w^3)/9# #= (sqrt(80) * sqrt(w^3))/9# #= (sqrt(4 * 4) * sqrt(5) * sqrt(w * w) * sqrt(w))/9# #=(4w*sqrt(5)*sqrt(w))/9# #= (4wsqrt(5w))/9# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2368 views around the world You can reuse this answer Creative Commons License