How do you simplify #\sqrt { 80x ^ { 2} y z}#?

1 Answer
Barney V.
Mar 3, 2017

#4x*sqrt2*sqrt5*sqrt(yz)# or #4x*2^(1/2)*5^(1/2)*y^(1/2)*z^(1/2)#

Explanation:

#sqrt(80x^2yz)#

#sqrt(cancel2*cancel2*cancel2*cancel2*2*5x^2yz#

#sqrt2*sqrt2=2,sqrt2*sqrt2=2#

#2*2*sqrt(2*5x^2yz)#

#4x*sqrt2*sqrt5*sqrt(yz)#

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