How do you simplify #sqrt18 * sqrt126#? Prealgebra Exponents, Radicals and Scientific Notation Square Root 1 Answer Alan P. May 4, 2016 #sqrt(18)*sqrt(126)= color(blue)(18sqrt(7))# Explanation: #sqrt(color(red)18)*sqrt(color(green)(126))# #color(white)("XXX")=sqrt(color(red)(3xx3xx2)xxcolor(green)(3xx3xx2xx7))# #color(white)("XXX")=3xx3xx2sqrt(7)# #color(white)("XXX")=18sqrt(7)# Answer link Related questions How do you simplify #(2sqrt2 + 2sqrt24) * sqrt3#? How do you simplify #sqrt735/sqrt5#? How do you rationalize the denominator and simplify #1/sqrt11#? How do you multiply #sqrt[27b] * sqrt[3b^2L]#? How do you simplify #7sqrt3 + 8sqrt3 - 2sqrt2#? How do you simplify #sqrt468 #? How do you simplify #sqrt(48x^3) / sqrt(3xy^2)#? How do you simplify # sqrt ((4a^3 )/( 27b^3))#? How do you simplify #sqrt140#? How do you simplify #sqrt216#? See all questions in Square Root Impact of this question 2267 views around the world You can reuse this answer Creative Commons License