# How do you simplify sqrt27?

$\sqrt{27} = \sqrt{3 \cdot 3 \cdot 3} = \sqrt{3} \sqrt{3} \sqrt{3} = \left({\sqrt{3}}^{2}\right) \sqrt{3} = 3 \sqrt{3}$
In general $\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$ and ${\left(\sqrt{a}\right)}^{2} = a$