# How do you simplify #sqrt27*sqrt33#?

##### 2 Answers

#### Answer:

9

#### Explanation:

= [*9] * [ #sqrt#3*11]

= [3

*11] ;*

= [3#sqrt# 3] * [#sqrt# 3] * [#sqrt# 11] ;

= 3#sqrt# 3

#sqrt# 27 becomes 3#sqrt# 3 because the sqrt of 9 is 3= [3

**we separate**#sqrt# 3 and #sqrt# 11= 3

**we multiply those with**#sqrt# 3

= 3

= 3 * 3 *

**there are two 3s now because again the sqrt of 9 is 3**

= 9

**FINAL ANSWER**

#### Answer:

First, before multiplying, you can simplify the √27.

#### Explanation:

=

Now we can multiply, multiplying radicals with radicals and whole numbers with whole numbers.

=

=

=

=

So,

**Practice exercises:**

- Simplify:

a)

b)

2 . Solve for x in

Good Luck!