How do you simplify  sqrt3^2?

Feb 3, 2016

Ambiguous

Explanation:

I cannot understand if the square is inside or outside the radix. Anyhow, if it's inside (the most plausible one...)
$\sqrt{{3}^{2}}$ it's one of the two numbers $\pm a$ such that ${\left(\pm a\right)}^{2} = {3}^{2} = 9$, so they are $\sqrt{{3}^{2}} = \pm 3$
On the other hand, if we consider ${\left(\sqrt{3}\right)}^{2}$, you gotta take both $\pm \sqrt{3}$ and take the square. But, by definition, $\pm \sqrt{3}$ are the only two numbers such that ${\left(\pm \sqrt{3}\right)}^{2} = 3$, so the answer is $3$

Feb 3, 2016

Ambiguous

Explanation:

I cannot understand if the square is inside or outside the radix. Anyhow, if it's inside (the most plausible one...)
$\sqrt{{3}^{2}}$ it's one of the two numbers $\pm a$ such that ${\left(\pm a\right)}^{2} = {3}^{2} = 9$, so they are $\sqrt{{3}^{2}} = \pm 3$
On the other hand, if we consider ${\left(\sqrt{3}\right)}^{2}$, you gotta take both $\pm \sqrt{3}$ and take the square. But, by definition, $\pm \sqrt{3}$ are the only two numbers such that ${\left(\pm \sqrt{3}\right)}^{2} = 3$, so the answer is $3$