How do you simplify #sqrt6*sqrt8#?
1 Answer
Mar 8, 2018
Explanation:
#"using the "color(blue)"law of radicals"#
#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#
#rArrsqrt6xxsqrt8#
#=sqrt(6xx8)=sqrt48#
#sqrt48=sqrt(16xx3)=sqrt16xxsqrt3=4sqrt3#
