# How do you simplify sqrt72-sqrt8+sqrt128?

Jul 29, 2016

$12 \sqrt{2}$

#### Explanation:

We'll just simplify each square root individually to start out:

$\sqrt{72} = 3 \sqrt{8} = 6 \sqrt{2}$

$\sqrt{8} = 2 \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$6 \sqrt{2} - 2 \sqrt{2} + 8 \sqrt{2} = 12 \sqrt{2}$