# How do you simplify (Square Root 26) times (square root 2) + 4 (Square Root 13)?

$3 \cdot \sqrt{52}$
$\sqrt{26} \cdot \sqrt{2} + 4 \cdot \sqrt{13}$
$= \sqrt{52} + 2 \cdot 2 \cdot \sqrt{13}$
$= \sqrt{52} + 2 \cdot \sqrt{4} \cdot \sqrt{13}$
$= \sqrt{52} + 2 \cdot \sqrt{52}$
$= 3 \cdot \sqrt{52}$