How do you simplify #(tan(x)+cos(x)) / sec^2(x)#?

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Answer 1 · 2015-07-22T17:14:11

cosx (sinx +#cos^2 #x)

=#cos^2 x (tan x+cosx)#

= #cos^2x (sinx + cos^2x)/cosx#

= cosx (sinx +#cos^2 #x)

Answer 2 · 2015-07-23T02:35:35

I guess that the question might be:
Simplify: #(tan x + cot x)/sec^2 x# ?

#(sin x/cos x + cos x/sin x)(cos^2 x) =$

#= ((sin^2 x + cos^2 x)/(sin x.cos x))(cos^2 x) = cos x/sin x# = cot x