# How do you simplify the expression (16x^4y-12x^5y^3)/(2x^3y^2)?

$\frac{8 x - 6 {x}^{2} {y}^{2}}{y}$
$\frac{\cancel{2 {x}^{3} y} \left(8 x - 6 {x}^{2} {y}^{2}\right)}{\cancel{2 {x}^{3} y} \left(y\right)}$
$\frac{8 x - 6 {x}^{2} {y}^{2}}{y}$