How do you simplify the expression # 6sqrt2 div sqrt3#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Kalyanam S. May 20, 2018 #color(green)(=> 2 sqrt6# Explanation: #(6sqrt2)/sqrt3# #=> (6 sqrt2 sqrt3) / (sqrt3 sqrt3)#, multiply and divide by #sqrt3# #=>(cancel (6)^color(red)(2) * sqrt6) / cancel3# #color(green)(=> 2 sqrt6# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1763 views around the world You can reuse this answer Creative Commons License