Question

How do you simplify the expression `sin^2tcottcsct`?

Answer 1

`cost`

Explanation:

`sin^2tcottcsct`

`=sin^2txxcost/sintxx1/sint`

`=(sin^2txxcostxx1)/(sintxxsint)`

`=(cancel(sin^2t)xxcost)/cancel(sin^2t)`

`=cost`