# How do you simplify the product (2r + 1)(3r - 1) and write it in standard form?

Jan 9, 2016

$6 {r}^{2} + r - 1$
$\left(2 r + 1\right) \left(3 r + 1\right) = 2 r \left(3 r - 1\right) + 1 \left(3 r - 1\right)$
$= 6 {r}^{2} - 2 r + 3 r - 1 = 6 {r}^{2} + r - 1$