How do you simplify #(w+2t)(w^2-2wt+4t^2)#?
1 Answer
Jul 28, 2018
Explanation:
The given expression is in the form:
#(A+B)(A^2-AB+B^2)#
with
This is recognisable as the factored form (using real coefficients) of the sum of cubes:
#A^3+B^3 = (A+B)(A^2-AB+B^2)#
If you wanted to multiply it out by hand, you could use distributivity as follows:
#(w+2t)(w^2-2wt+4t^2) = w(w^2-2wt+4t^2)+2t(w^2-2wt+4t^2)#
#color(white)((w+2t)(w^2-2wt+4t^2)) = w^3-color(red)(cancel(color(black)(2w^2t)))+color(green)(cancel(color(black)(4wt^2)))+color(red)(cancel(color(black)(2w^2t)))-color(green)(cancel(color(black)(4wt^2)))+8t^3#
#color(white)((w+2t)(w^2-2wt+4t^2)) = w^3+8t^3#