How do you simplify #x^ { 2} \cdot x ^ { - 12}#?
1 Answer
Feb 3, 2018
Explanation:
#"using the "color(blue)"laws of exponents"#
#•color(white)(x)a^nxxa^m=a^((m+n))#
#•color(white)(x)a^-m=1/a^m#
#rArrx^2xx x^(-12)#
#=x^((2-12))#
#=x^(-10)#
#=1/x^(10)larrcolor(blue)"expressed with positive exponent"#
