Question

How do you simplify `x^{2}\times \log _{x}27\times \log _{9}x=x+4`?

Answer 1

See below.

Explanation:

`log_x 3^3 xx log_(3^2)x = (x+4)/x^2`

`(log_e3^3)/log_e x log_e x/log_e 3^2 = 3/2= (x+4)/x^2` or

`3x^2-2(x+4)=0` or `x = 2` as the feasible solution