How do you simplify #(x+3)(x+3)#?

1 Answer
Mar 26, 2018

Answer:

#x^2+6x+9#

Explanation:

#"each term in the second factor is multiplied by each term"#
#"in the first factor"#

#rArr(color(red)(x+3))(x+3)#

#=color(red)(x)(x+3)color(red)(+3)(x+3)larrcolor(blue)"distribute"#

#=(color(red)(x)xx x)+(color(red)(x)xx3)+(color(red)(3)xx x)+(color(red)(3)xx3)#

#=x^2+3x+3x+9larrcolor(blue)"collect like terms"#

#=x^2+6x+9#