How do you simplify #(x + 6) ( x + 1) ( x + 4)#?
1 Answer
Nov 16, 2016
Explanation:
Note that:
#(x+a)(x+b)(x+c)#
#= x^3+(a+b+c)x^2+(ab+bc+ca)x+abc#
The polynomials:
#{ (a+b+c), (ab+bc+ca), (abc) :}#
are called the elementary symmetric polynomials in
Whatever they're called, notice the ways in which we need to collect the coefficients to multiply the
Hence we find:
#(x+6)(x+1)(x+4) = x^3+(6+1+4)x^2+(6*1+1*4+4*6)x+6*1*4#
#color(white)((x+6)(x+1)(x+4)) = x^3+11x^2+34x+24#