How do you simplify #(x + 6) ( x + 1) ( x + 4)#?

1 Answer
Nov 16, 2016

#(x+6)(x+1)(x+4) = x^3+11x^2+34x+24#

Explanation:

Note that:

#(x+a)(x+b)(x+c)#

#= x^3+(a+b+c)x^2+(ab+bc+ca)x+abc#

The polynomials:

#{ (a+b+c), (ab+bc+ca), (abc) :}#

are called the elementary symmetric polynomials in #a#, #b# and #c#. Interestingly, any symmetric polynomial in #a#, #b# and #c# is expressible in terms of these three elementary ones.

Whatever they're called, notice the ways in which we need to collect the coefficients to multiply the #3# binomials.

Hence we find:

#(x+6)(x+1)(x+4) = x^3+(6+1+4)x^2+(6*1+1*4+4*6)x+6*1*4#

#color(white)((x+6)(x+1)(x+4)) = x^3+11x^2+34x+24#