# How do you simplify y^-1/ (y^4)^2?

Apr 11, 2018

Should be $\frac{1}{y} ^ 9$

#### Explanation:

For example: $\frac{{y}^{-} 1}{y} ^ 8$
Next, you have to flip the ${y}^{-} 1$ so that it positive because it's math illiteracy to leave a negative exponent:
$\frac{1}{y} ^ 9$
${y}^{2} \cdot {y}^{3} = {y}^{5}$ but ${\left({y}^{2}\right)}^{3} = {y}^{6}$