How do you simpligy #4\sqrt{x} = \sqrt{9x + 9}#?
1 Answer
Oct 5, 2016
#x=9/7#
Explanation:
Given -
#4sqrtx=sqrt(9x+9)#
Square both sides
#[4sqrtx]^2=[sqrt(9x+9)]^2#
#16x=9x+9#
Add
#16x-9x=cancel(9x)+9cancel(-9x)#
#7x=9#
#x=9/7#
