# How do you sketch one cycle of y=-sin2x?

Oct 8, 2017

$y = \sin \left(2 x\right)$
graph{sin(2x) [-10, 10, -5, 5]}

#### Explanation:

$y = - \sin \left(2 x\right)$
$x = 0 , y = 0$
$x = \frac{\pi}{4} , y = - 1$
$x = \frac{\pi}{2} , y = 0$
$x = \left(- \frac{\pi}{4}\right) , y = 1$
With these values, we can plot the graph.