# How do you sketch the angle in standard position (2pi)/9?

Aug 9, 2018

See graph and and explanation.

#### Explanation:

The direction angle theta = 2/9pi = (2/9(180)^o = 40^o.

The Cartesian $P \left(1 , \tan {40}^{o}\right) = \left(1 , 0.8391\right)$.

In polar coordinates, it is $P \left(O P , {40}^{o}\right)$

$= P \left(\sqrt{{1}^{2} + {\left(0.8391\right)}^{2}} , {40}^{o}\right) = P \left(1.2054 , {40}^{o}\right)$. See grapk.

graph{(arctan(y/x) - 2/9pi)((x-1)^2 + (y- tan(2/9pi))^2-0.0005)=0[0 2 0 1]}