# How do you sketch the angle whose terminal side in standard position passes through (4,-3) and how do you find sin and cos?

Nov 11, 2016

$\sin t = - \frac{3}{5}$
$\cos t = \frac{4}{5}$

#### Explanation:

consider the right triangle 0AB with
OA = 4 ; AB = -3
Then, hypotenuse OB = 5 (Ratio 3:4:5)
We have, calling t the angle <AOB:
$\cos t = O \frac{A}{O} B = \frac{4}{5}$
$\sin t = - A \frac{B}{O} B = - \frac{3}{5}$