How do you sketch the angle whose terminal side in standard position passes through #(-9,-40)# and how do you find sin and cos?
The point (x = -9, y = -40) is on the terminal side of the angle t, that lies in Quadrant 3.
tan t = y/x = -40/-9 = 40/9
To find cos t, use trig identity:
Another way to find sin t: