How do you sketch the graph of #y=-4(x+1)^2-5# and describe the transformation?
1 Answer
Feb 7, 2018
Refer explanation section
Explanation:
Given -
#y=-4(x+1)^2-5#
It is a parabola equation in the intercept form
#y=a(x+h)^2+k#
Where -
#(h, k)# is the vertex.
In the given equation -
#(-1, -5)# is the vertex.
Choose a few points on either side of the vertex
Find the corresponding
Tabulate them -
Plot all the points. Join with a smooth line
