How do you solve #0.1x + 0.6y = -1# and #0.2x - 0.7y = 3.7# using substitution?

1 Answer
Jul 25, 2016

Answer:

#x=-3#
#y=-7/6#

Explanation:

#0.1x+0.6y=-1#
Multiplying both sides by 10 we get
#x+6y=-10#
Similarly multiplying both sides of #0.2x-0.7y=3.7#by 10
we get
#2x-7y=37#
Similarly multiplying both sides of #x+6y=-10# by #2#
we get
#2x+12y=-20#
Subtracting #2x-7y=37# from #2x+12y=-20#
we get
#2x+12y-2x+7y=-20-37#
or
#19x=-57#
or
#x=-57/19#
or
#x=-3#------------Ans#1#

Since from above we have Equation #x+6y=-10#
By putting value of x=-3 in the above equation we get
#-3+6y=-10#
or
#6y=-7#
or
#y=-7/6#------------Ans#2#