Question

How do you solve `0.3x-0.2y=4` and `0.4x+0.5y=63/19` using substitution?

Answer 1

`x=220/19,y=-50/19`

Explanation:

writing your System in the form

`3x-2y=40`
`4x+5y=630/19`
so we get from the first equation

`y=3/2x-20`
plugging this in the second equation we get

`4x+5(3/2x-20)=630/19`
`x=220/19`

`y=-50/19`