# How do you solve 0.3x-0.2y=4 and 0.4x+0.5y=63/19 using substitution?

Jun 20, 2018

$x = \frac{220}{19} , y = - \frac{50}{19}$

#### Explanation:

writing your System in the form

$3 x - 2 y = 40$
$4 x + 5 y = \frac{630}{19}$
so we get from the first equation

$y = \frac{3}{2} x - 20$
plugging this in the second equation we get

$4 x + 5 \left(\frac{3}{2} x - 20\right) = \frac{630}{19}$
$x = \frac{220}{19}$

$y = - \frac{50}{19}$