How do you solve #0.5( 2x - 9) - 11= 0.25( 22- 8x )#?

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Answer 1 · 2017-04-14T06:30:39

#x=7#

We have: #0.5(2x-9)-11=0.25(22-8x)#

That can be written as: #(2x-9)/2-11=(22-8x)/4#

We can multiply both sides by #4#:

#2(2x-9)-44=(22-8x)#

#4x-18-44=22-8x#

Collect all the unknown values:

#4x+8x=18+44+22#

#12x=84#

#x=7#

To check, insert #7# into the #given# equation:

#0.5(2x-9)-11=0.25(22-8x)#

#0.5(2*7-9)-11=0.25(22-8*7)#

#0.5(14-9)-11=0.25(22-56)#

#0.5(5)-11=0.25(-34)#

#2.5-11=-34/4#

#-17/2=-34/4#