How do you solve # 1- ( 2n + 9) = 4( n - 2)#?

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Answer 1 · 2016-11-02T13:38:34

#n = 0#

Step 1) Expand the terms in the parenthesis
Step 2) Combine like terms
Step 3) Solve for #n#

#1 - 2n - 9 = 4n - 8#

#-2n - 8 = 4n - 8#

#-2n - 8 + 2n + 8 = 4n - 8 + 2n + 8#

#0 = 6n#

#0/6 = (6n)/6#

#n = 0#