How do you solve #1/2x + 3 = 9#?

2 Answers
Mar 7, 2018

Answer:

#x=12#

Explanation:

#"subtract 3 from both sides"#

#1/2xcancel(+3)cancel(-3)=9-3#

#rArr1/2x=6#

#"multiply both sides by 2"#

#cancel(2)xx1/cancel(2)x=2xx6#

#rArrx=12" is the solution"#

Mar 7, 2018

Answer:

See a solution process below:

Explanation:

First, subtract #color(red)(3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#1/2x + 3 - color(red)(3) = 9 - color(red)(3)#

#1/2x + 0 = 6#

#1/2x = 6#

Now, multiply each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#color(red)(2) xx 1/2x = color(red)(2) xx 6#

#color(red)(2)/2x = 12#

#1x = 12#

#x = 12#