Question

How do you solve `1/2x + 3 = 9`?

Answer 1

`x=12`

Explanation:

`"subtract 3 from both sides"`

`1/2xcancel(+3)cancel(-3)=9-3`

`rArr1/2x=6`

`"multiply both sides by 2"`

`cancel(2)xx1/cancel(2)x=2xx6`

`rArrx=12" is the solution"`

Answer 2

See a solution process below:

Explanation:

First, subtract `color(red)(3)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`1/2x + 3 - color(red)(3) = 9 - color(red)(3)`

`1/2x + 0 = 6`

`1/2x = 6`

Now, multiply each side of the equation by `color(red)(2)` to solve for `x` while keeping the equation balanced:

`color(red)(2) xx 1/2x = color(red)(2) xx 6`

`color(red)(2)/2x = 12`

`1x = 12`

`x = 12`