How do you solve #1.2x + 8 < 9.6# and graph the solution graph the solution on a number line?

2 Answers
Feb 19, 2018

Answer:

#x<1.333#

Explanation:

Move the #8# over so you have

#1.2x<1.6#

Then divide both sides by #1.2#. This will give you

#x < 1.6/1.2#

#x < 1.333...#

So in the end, you have #x<1.333# (notice that the sign doesn't change because there is no multiplication/division by a negative).

Then you would just put an arrow going left to negative infinity starting at #1.333# with an open circle. :)

Feb 19, 2018

Answer:

See a solution process below:

Explanation:

First, subtract #color(red)(8)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#1.2x + 8 - color(red)(8) < 9.6 - color(red)(8)#

#1.2x + 0 < 1.6#

#1.2x < 1.6#

Next, divide each side of the inequality by #color(red)(1.2)# to solve for #x# while keeping the inequality balanced:

#(1.2x)/color(red)(1.2) < 1.6/color(red)(1.2)#

#(color(red)(cancel(color(black)(1.2)))x)/cancel(color(red)(1.2)) < 10/10 xx 1.6/color(red)(1.2)#

#x < 16/12#

#x < 4/3#

Or

#x < 1 1/3#

To graph this on the number line we need to put a hollow point at #1 1/3# on the number line because the inequality does not contain an "or equal to" clause. Therefore, #1 1/3# is not part of the solution set.

Then from that point we draw an arrow to the left because the inequality is a "less than" operator:

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