# How do you solve #1+ 3a = - 8- 4a#?

##### 2 Answers

#### Explanation:

#"collect terms in a on the left and numeric values on the "#

#"right side of the equation"#

#"add 4a to both sides"#

#1+3a+4a=-8cancel(-4a)cancel(+4a)#

#rArr1+7a=-8#

#"subtract 1 from both sides"#

#cancel(1)cancel(-1)+7a=-8-1#

#rArr7a=-9#

#"divide both sides by 7"#

#(cancel(7) a)/cancel(7)=(-9)/7#

#rArra=-9/7#

#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=7/7-27/7=-20/7#

#"right "=-56/7+36/7=-20/7#

#rArra=-9/7" is the solution"#

#### Explanation:

1) Add

After you have added, you get this:

2) Subtract

After you subtract, you will have this:

3) Divide both sides by

**Check**

1) Sub in

2) Clear the parentheses by distributing the coefficients

3) To add, give the whole numbers the common denominator of

4) Add like terms