How do you solve #1/8=1/16d#?

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Answer 1 · 2016-09-20T21:09:17

#d = 2#

Rewrite as #d/16 =1/8#

Multiply both sides by 16 to cancel the denominator.

#(cancel16xxd)/cancel16 =(cancel16^2xx1)/cancel8#

#d = 2#

The reslt would be the same from cross-multiplying.

#8d = 16#

#d = 16/8#

#d = 2#