# How do you solve 1<(a-8)/9?

Nov 14, 2016

$a > 17$

#### Explanation:

Step 1) Multiple each side of the inequality by $9$ to eliminate the fraction:

$9 \times 1 < 9 \times \frac{a - 8}{9}$

$9 \times 1 < \left(\frac{9}{9}\right) \times \left(a - 8\right)$

$9 < 1 \times \left(a - 8\right)$

$9 < a - 8$

Step 2) Solve for $a$ while keeping both sides of the inequality balanced:

$9 + 8 < a - 8 + 8$

$17 < a - 0$

$17 < a$

Step 3) Reverse the inequality to put in terms of $a$

$a > 17$