How do you solve #10 + 2/3t=6#? Algebra Linear Equations Two-Step Equations and Properties of Equality 1 Answer GM_Phrostbyte Jul 1, 2017 #-6# Explanation: To isolate #t#, you must first subtract 10 from both sides of the equation: #10+t2/3-10=6-10# #2/3t=-4# Then, to cancel out the effect of the #2/3# on the #t#, you can multiply both sides by the recipricol of 2/3 which is 3/2 #(2/3*3/2)t=-4*3/2# #t=-12/2# #t=-6# Answer link Related questions How do you solve two step equations? How do you check solutions to two step equations? What is an example of a two step equation with no solution? How do I check to see if the solution is 1 for the equation #2x+1=3#? Is there more than one way to solve a 2 step equation? How do you solve #-m+3=3#? How do you solve #-5y-9=74#? How do you solve #5q - 7 = \frac{2}{3}#? How do you solve #0.1y + 11 =0#? How do you solve #\frac{5q-7}{12} = \frac{2}{3}#? See all questions in Two-Step Equations and Properties of Equality Impact of this question 1586 views around the world You can reuse this answer Creative Commons License