How do you solve #10q + - 7q + q = 8#?

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Answer 1 · 2018-04-27T12:46:50

See a solution process below:

First, combine like terms on the left side of the equation:

#10q + -7q + q = 8#

#10q + -7q + 1q = 8#

#(10 + -7 + 1)q = 8#

#(10 - 7 + 1)q = 8#

#(3 + 1)q = 8#

#4q = 8#

Now, divide each side of the equation by #color(red)(4)# to solve for #q# while keeping the equation balanced:

#(4q)/color(red)(4) = 8/color(red)(4)#

#(color(red)(cancel(color(black)(4)))q)/cancel(color(red)(4)) = 2#

#q = 2#