# How do you solve -10x^2 + 30x - 20 = 0.?

May 27, 2018

$x = 2 , 1$

#### Explanation:

given, $- 10 {x}^{2} + 30 x - 20 = 0$
Multiplying both sides with $- 1$
we get,
$10 {x}^{2} - 30 x + 20 = 0$

By Using quadratic formula $\left\{x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}\right\}$
we get,

$\Rightarrow x = \frac{30 \pm \sqrt{{30}^{2} - 4 \cdot 10 \cdot 20}}{2 \cdot 10}$
$\Rightarrow x = \frac{30 \pm 10}{20}$
$\Rightarrow x = \frac{40}{20} , x = \frac{20}{20}$
Thus we get the value of $x$ as $x = 2 , 1$

May 27, 2018

$x = 2$
$x = 1$

#### Explanation:

Given -

$- 10 {x}^{2} + 30 x - 20 = 0$

$- 10 \left({x}^{2} - 3 x + 2\right) = 0$

Dividing both sides by 10 we get

${x}^{2} - 3 x + 2 = 0$

${x}^{2} - x - 2 x + 2 = 0$

$x \left(x - 1\right) - 2 \left(x - 1\right) = 0$

$\left(x - 2\right) \left(x - 1\right) = 0$

$x - 2 = 0$

$x = 2$

$x - 1 = 0$

$x = 1$