Question

How do you solve `11( x - 7)^{2} = 289`?

Answer 1

`x = 7+-(17sqrt11)/11`

`~~12.13` and `1.87`

Explanation:

`11( x - 7)^{2} = 289`

`(11( x - 7)^{2})/11 = 289/11`

`( x - 7)^{2} = 289/11`

`sqrt(( x - 7)^{2} )= +-sqrt(289/11)`

`x - 7= +-17/sqrt11`

`x - 7= +-(17sqrt11)/11`