How do you solve #11x^2 - x - 3 = 0#?

1 Answer
May 8, 2018

Answer:

#x=1/22+-1/22sqrt133#

Explanation:

#"this quadratic does not factorise with whole number values"#

#"solve using the "color(blue)"quadratic formula"#

#•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)#

#11x^2-x-3=0larrcolor(blue)"is in standard form"#

#"with "a=11,b=-1" and "c=-3#

#rArrx=(1+-sqrt(1+132))/22=(1+-sqrt133)/22#

#rArrx=1/22+-1/22sqrt133larrcolor(red)"exact solutions"#

#rArrx~~-0.48" or "x~~0.57" to 2 dec. places"#