How do you solve 12(10b -9) > -12(9+8b)?

Apr 23, 2018

$b > 0$

Explanation:

$12 \left(10 b - 9\right) > - 12 \left(9 + 8 b\right)$
Divide both sides by 12:
$\left(10 b - 9\right) > - \left(9 + 8 b\right)$
On the right side distribute the negative sign inside parentheses:
$10 b - 9 > - 9 - 8 b$
Add 9 to both sides:
$10 b > - 8 b$
Add 8b to both sides:
$18 b > 0$
Divide both sides by 18:
$b > 0$
In interval form:
$\left(0 , \infty\right)$