How do you solve #-12= - 2w#?

1 Answer
Mar 11, 2017

#w = 6#

Explanation:

In this problem, you would divide both sides of the equation by #-2# to separate the #w# from the rest of the problem. Dividing the #-2w# by #-2# would result in the #w# being alone on one side of the equation.

Then you would divide the #-12# by #-2#, getting #6# being equal to #w#.

#(-12)/-2 = (-2w)/-2#

#6 = w#