# How do you solve 12<8+x?

Jun 21, 2018

$x > 4$

#### Explanation:

Subtract $8$ from both sides to get

$12 - 8 < \cancel{8} + x - \cancel{8}$

The left hand side becomes $12 - 8 = 4$ and so we have

$4 < x$

which is the same as

$x > 4$