How do you solve 12x^2-15x= 0 using the quadratic formula?

1 Answer
Jun 19, 2016

$x = 0 \mathmr{and} x = \frac{5}{4}$

Explanation:

Before you apply the quadratic formula, consider

a=12
b=-15
c=0

so, by substituting in the formula

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$,

you find

$x = \frac{15 \pm \sqrt{225 - 4 \cdot 12 \cdot 0}}{2 \cdot 12}$

$x = \frac{15 \pm 15}{24}$

$x = 0 \mathmr{and} x = \frac{30}{24} = \frac{5}{4}$