# How do you solve #12x^2 + 2x = 0#?

##### 1 Answer

#### Answer:

#### Explanation:

You can solve this quadratic by factoring it to the form

The product of two *distinct* terms is equal to zero if either one of those terms is equal to **zero**, so you have

#2x = 0# or#(6x+1) = 0#

The solutions to these equations are

and

**Alternatively**, you could use the general quadratic form

#color(blue)(ax^2 + bx + c = 0)#

and recognize that *quadratic formula*

#color(blue)(x_(1,2) = (-b +- sqrt(b^2 - 4ac))/(2a)#

is reduced to

#x_(1,2) = (-b +- sqrt(b^2 + 4 * a * 0))/(2a) = (-b +- b)/(2a)#

In your case,