How do you solve #12x - 28=4x - 36#?

1 Answer
smendyka
Mar 28, 2018

See a solution process below:

Explanation:

First, add #color(red)(28)# and subtract #color(blue)(4x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#12x - color(blue)(4x) - 28 + color(red)(28) = 4x - color(blue)(4x) - 36 + color(red)(28)#

#(12 - color(blue)(4))x - 0 = 0 - 8#

#8x = -8#

Now, divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equality balanced:

#(8x)/color(red)(8) = -8/color(red)(8)#

#(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = -1#

#x = -1#

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