How do you solve #12y = - 1344#?

1 Answer
smendyka
Jun 19, 2017

See a solution process below:

Explanation:

Divide each side of the equation by #color(red)(12)# to solve for #y# while keeping the equation balanced:

#(12y)/color(red)(12) = -1344/color(red)(12)#

#(color(red)(cancel(color(black)(12)))y)/cancel(color(red)(12)) = -112#

#y = -112#

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