How do you solve 14^(x+1) = 36?

1 Answer
Apr 19, 2016

Take the logarithm of each side. A logarithm rule lets us take the exponent outside of the logarithm.

Explanation:

14^{x+1}=36

ln(14^{x+1})=ln(36)

(x+1)*ln(14)=ln(36)

(x+1)=ln(36)/{ln(14)}

x=ln(36)/{ln(14)}-1

x\approx 0.357878

Substitute x into the problem to check the answer.