Question

How do you solve `-15x-2=25`?

Answer 1

`x=-27/15`

Explanation:

`"add 2 to both sides of the equation"`

`-15xcancel(-2)cancel(+2)=25+2`

`rArr-15x=27`

`"divide both sides by "-15`

`(cancel(-15) x)/cancel(-15)=27/(-15)`

`rArrx=-27/15`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`(-15xx-27/15)-2=27-2=25`

`rArrx=-27/15" is the solution"`